Detecting If A Character In A String Is An Emoticon (using Android)

Like the title says. I want to find out if a given java String contains an emoticon. I can't use Character.UnicodeBlock.of(char) == Character.UnicodeBlock.EMOTICONS since that requ

Solution 1:

Four years later...

At this time, it might make more sense to take advantage of EmojiCompat. This code presumes you initialized EmojiCompat when your app was starting up. The basic idea here is to have EmojiCompat process your CharSequence, inserting instances of EmojiSpan wherever any emoji appear, and then examine the results.

publicstaticbooleancontainsEmoji(CharSequence charSequence) {
    booleanresult=false;
    CharSequenceprocessed= EmojiCompat.get().process(charSequence, 0, charSequence.length() -1, Integer.MAX_VALUE, EmojiCompat.REPLACE_STRATEGY_ALL);
    if (processed instanceof Spannable) {
        Spannablespannable= (Spannable) processed;
        result = spannable.getSpans(0, spannable.length() - 1, EmojiSpan.class).length > 0;
    }
    return  result;
}

If you want to collect a list of the unique emoji that appear within a given CharSequence, you could do something like this, iterating over the results of getSpans() and finding the start and end of each span to capture the emoji discovered by EmojiCompat:

@NonNull
publicstaticList<String> getUniqueEmoji(CharSequence charSequence) {
    Set<String> emojiList = new HashSet<>();
    CharSequence processed = EmojiCompat.get().process(charSequence, 0, charSequence.length() -1, Integer.MAX_VALUE, EmojiCompat.REPLACE_STRATEGY_ALL);
    if (processed instanceof Spannable) {
        Spannable spannable = (Spannable) processed;

        EmojiSpan[] emojiSpans = spannable.getSpans(0, spannable.length() - 1, EmojiSpan.class);
        for (EmojiSpan emojiSpan : emojiSpans) {
            int spanStart = spannable.getSpanStart(emojiSpan);
            int spanEnd = spannable.getSpanEnd(emojiSpan);
            CharSequence emojiCharSequence = spannable.subSequence(spanStart, spanEnd);
            emojiList.add(String.valueOf(emojiCharSequence));
        }
    }
    return emojiList.size() > 0 ? new ArrayList<>(emojiList) : new ArrayList<String>();
}

UPDATE: Here's an example of EmojiCompat initialization. This static method can be called from your Application onCreate() method, passing in the Application itself as the Context param.

@JvmStaticfuninitEmojiCompat(context: Context) {
    if (emojiCompatConfig != null) {
        // alternatively, EmojiCompat.reset() could be called here
        logger().w(LOGTAG, "EmojiCompat already initialized.")
        return
    }

    // "Noto Color Emoji Compat" doesn't have graphics for the following emojis:// U+1F5E3 "speaking head" (required)// U+1F441 "eye" (required)// U+1F575 "detective" (nice to have)val fontRequest = FontRequest(
        "com.google.android.gms.fonts",
        "com.google.android.gms",
        "Noto Color Emoji Compat",
        R.array.com_google_android_gms_fonts_certs
    )

    emojiCompatConfig = FontRequestEmojiCompatConfig(context, fontRequest)
        .setReplaceAll(false)
        .setEmojiSpanIndicatorEnabled(false)
        .registerInitCallback(initCallback)
        .also {
            EmojiCompat.init(it)
        }
}

Solution 2:

I was in fact able to use the linked iOS code to create the following function. I didn't realize that a String that contains, for example, a single emoticon will have a length of 2. So you can check if a character is in fact a surrogate.

I'm not entirely sure how to handle else if (substring.length > 1) from the iOS code but I think Character.isHighSurrogate(myChar) does the same job in that instance.

private boolean containsIllegalCharacters(String displayName)
{
    final int nameLength = displayName.length();

    for (int i = 0; i < nameLength; i++)
    {
        final char hs = displayName.charAt(i);

        if (0xd800 <= hs && hs <= 0xdbff)
        {
            final char ls = displayName.charAt(i + 1);
            final int uc = ((hs - 0xd800) * 0x400) + (ls - 0xdc00) + 0x10000;

            if (0x1d000 <= uc && uc <= 0x1f77f)
            {
                returntrue;
            }
        }
        elseif (Character.isHighSurrogate(hs))
        {
            final char ls = displayName.charAt(i + 1);

            if (ls == 0x20e3)
            {
                returntrue;
            }
        }
        else
        {
            // non surrogateif (0x2100 <= hs && hs <= 0x27ff)
            {
                returntrue;
            }
            elseif (0x2B05 <= hs && hs <= 0x2b07)
            {
                returntrue;
            }
            elseif (0x2934 <= hs && hs <= 0x2935)
            {
                returntrue;
            }
            elseif (0x3297 <= hs && hs <= 0x3299)
            {
                returntrue;
            }
            elseif (hs == 0xa9 || hs == 0xae || hs == 0x303d || hs == 0x3030 || hs == 0x2b55 || hs == 0x2b1c || hs == 0x2b1b || hs == 0x2b50)
            {
                returntrue;
            }
        }
    }

    returnfalse;
}

Solution 3:

Try this...

if (Integer.parseInt("1f600", 16) <= (int)'☺' && (int)'☺' <= Integer.parseInt("1f64f", 16)) {
    Print.d("Unicode", "groovy!");
}

This might work because the hexidecimal value and the char value are both being converted to ints.